LambentPyro Posted January 6, 2014 Share Posted January 6, 2014 Is there any formulas that call for Red Copper Oxide? If anyone has tried it instead of using Cupric Oxide, does it produce better results? Seems interesting and not a topic that I come by often. This pottery store sells it, I'm thinking about getting a lb.http://www.axner.com/copper-oxide-red.aspx Link to comment Share on other sites More sharing options...
pyrojig Posted January 6, 2014 Share Posted January 6, 2014 If it is cheap , I would say grab a lb. Im sure the results will be close to the black. If the mesh size is the same I would say do a side by side test in a comp. The use in thermite will not care which type it is , but colored stars will be the real test. Link to comment Share on other sites More sharing options...
schroedinger Posted January 6, 2014 Share Posted January 6, 2014 You could try it, but don't expect to much from it. If i remember right it was Cu2O. Which got nearly 50% less oxigen then the Black stuff. I would expect to maybe be an ok coloring agent, but not a good oxiders at al Link to comment Share on other sites More sharing options...
LambentPyro Posted January 6, 2014 Author Share Posted January 6, 2014 (edited) I'm not planning to use it in thermite but in colored star comps. It is pretty expensive from the supplier I listed in the OP, but I may still want to do a comparison as there is more Copper present than Oxygen. Edited January 6, 2014 by LambentPyro Link to comment Share on other sites More sharing options...
Mumbles Posted January 6, 2014 Share Posted January 6, 2014 I've heard reference to a few formulas that use copper (I) oxide, but I've never actually seen them. I thought I had one for violet, but after looking at my notes, it seems the guy I got it from was initially mistaken and later corrected himself. About all he's told me is that he has a copper (I) oxide and barium nitrate based turquoise(aqua), and possibly some spanish and italian purples and blues. Link to comment Share on other sites More sharing options...
LambentPyro Posted January 6, 2014 Author Share Posted January 6, 2014 (edited) I heard that Copper (I) Oxide after a while oxidizes further into Copper (II) Oxide, I'm not sure where I remember hearing that. Can it do that? An ion changing its amount of valence electrons without forcefully using chemicals? Edited January 6, 2014 by LambentPyro Link to comment Share on other sites More sharing options...
Mumbles Posted January 6, 2014 Share Posted January 6, 2014 Yes, chemicals can do that. It'll either be oxidized by air, or undergo disproportionation into Copper (0) and Copper (II). I don't know what the situation is with Copper (I) oxide though, or how sensitive it is to either. Link to comment Share on other sites More sharing options...
LambentPyro Posted January 6, 2014 Author Share Posted January 6, 2014 Yes, chemicals can do that. It'll either be oxidized by air, or undergo disproportionation into Copper (0) and Copper (II). I don't know what the situation is with Copper (I) oxide though, or how sensitive it is to either.Interesting, I have never heard of Copper (0) before, you're saying it disproportionates into an atom without a valence shell? Link to comment Share on other sites More sharing options...
Mumbles Posted January 7, 2014 Share Posted January 7, 2014 Copper (0) definitely exists, and it still has a valence shell. Being full, doesn't mean it doesn't exist. If it did, Copper (I) wouldn't be considered to have a valence shell. Disproportionate means one thing splits into two unequal things. Comproportionation is the opposite, where you take two different oxidation states and mix them to create a single oxidation state. You actually can make some copper (I) salts that way, such as the chloride, by mixing copper (II) salts with copper metal. Link to comment Share on other sites More sharing options...
LambentPyro Posted January 7, 2014 Author Share Posted January 7, 2014 Copper (0) definitely exists, and it still has a valence shell. Being full, doesn't mean it doesn't exist. If it did, Copper (I) wouldn't be considered to have a valence shell. Disproportionate means one thing splits into two unequal things. Comproportionation is the opposite, where you take two different oxidation states and mix them to create a single oxidation state. You actually can make some copper (I) salts that way, such as the chloride, by mixing copper (II) salts with copper metal. Yea, it makes sense now, Ferric Chloride can be made from Ferrous Choride through oxidation with air or H2O2, right? Link to comment Share on other sites More sharing options...
Recommended Posts