Comp Loading Pressure P to F conversion Help

[rocketboy242]

 

Looking for help to convert 7000lbs force on comp to psi on the following.

Piston bore is 3" diameter, the ram rod is 1 -1/4"  diameter, and I am using a 3/4"  solid rammer on the comp.

I want to achieve 7000lds of force on the comp.

please provide the the target on the psi gage attached and the conversion formula if possible.

Thank you

 

Edited March 12 by rocketboy242
wrong pic

[Carbon796]

Piston bore and ram rod ? Is the hydraulic cylinder that's on your press ? If so, that information isn't need. 

Assuming that your ptof gage is direct reading. Surface area of 3/4"tooling is .4418 x 7000psi = 3092.6 on your gage.

[rocketboy242]

Thanks for the reply,

Yes, I have a hydraulic press with a 3" diameter cylinder pushing an 1-1/4" rod that in turn pushes on the 3/4" drift.

I understand that the 1-1/4" rod doesn't factor in but I thought the cylinder diameter factored into the equation some how?

so 3092 psi on the gage?

That seems too high?

[Carbon796]

The cylinder diameter would only come into play. If you were reading the actual pressure being applied to the cylinder. And not using a PtoF gage. Think of the PtoF gage as a short cut. Your reading the actual force being applied through the 3/4" rammer. Regardless of what pressure may be developed in the press cylinder, or its piston size.

[rocketboy242]

My apologies for not clarifying.

The pressure gage is reading the pressure off the hydraulic cylinder. I don't have a pressure to force gage.

[Carbon796]

In that case " I think " you're going to want 438psi on your cylinder gage.

Piston surface area 7.069 x 438 = 3096.2 force applied to 3/4 rammer.

You may want to get ahold of rocket master Dave F. 

 

Edited March 13 by Carbon796

[DavidF]

Lol, my math stinks! I use charts that came with my first Wolter tooling and a P to F gauge. I'm thinking this is more of a Frank Rizzo question?

[rocketboy242]

Thanks for the help guys!